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Theory and Modern Applications

Table 1 Boundary condition ( 3.50 ) with g=0

From: Difference boundary value problem hierarchies and the forward Crum transformation

 

Original BVP: (1.1) with bc’s …

Trans. BVP: (2.2) with bc’s …

1

(3.20) and (3.50) with g = 0

(3.21) and (3.51)

 

z does not obey (3.20) or (3.50)

s + 1 + p + 1 + m − 1 eigenvalues

 

s + p + m eigenvalues

i.e. one extra eigenvalue 0

2

(3.20) and (3.50) with g = 0

(3.22) and (3.51)

 

z obeys (3.20) but not (3.50)

s + p + 1 + m − 1 eigenvalues

 

s + p + m eigenvalues

i.e. same eigenvalues

3

(3.20) and (3.50) with g = 0

(3.21) and (3.53)

 

z obeys (3.50) but not (3.20)

s + 1 + p + m − 1 eigenvalues

 

s + p + m eigenvalues

i.e. same eigenvalues

4

(3.20) and (3.50) with g = 0

(3.22) and (3.53)

 

z obeys both (3.20) and (3.50)

s + p + m − 1 eigenvalues

 

s + p + m eigenvalues

i.e. one less eigenvalue 0

5

(3.28) and (3.50) with g = 0

(3.29) and (3.51)

 

z does not obey (3.28) or (3.50), a= − c ( m ) c ( m − 1 )

s + p + 1 + m + 1 eigenvalues

 

s + p + m + 1 eigenvalues

i.e. one extra eigenvalue 0

6

(3.28) and (3.50) with g = 0

(3.31) and (3.51)

 

z obeys (3.28) but not (3.50), a= − c ( m ) c ( m − 1 )

s − 1 + p + 1 + m + 1 eigenvalues

 

s + p + m + 1 eigenvalues

i.e. same eigenvalues

7

(3.28) and (3.50) with g = 0

(3.29) and (3.53)

 

z obeys (3.50) but not (3.28), a= − c ( m ) c ( m − 1 )

s + p + m + 1 eigenvalues

 

s + p + m + 1 eigenvalues

i.e. same eigenvalues

8

(3.28) and (3.50) with g = 0

(3.31) and (3.53)

 

z obeys both (3.28) and (3.50), a= − c ( m ) c ( m − 1 )

s − 1 + p + m + 1 eigenvalues

 

s + p + m + 1 eigenvalues

i.e. one less eigenvalue 0

9

(3.28) and (3.50) with g = 0

(3.30) and (3.51)

 

z does not obey (3.28) or (3.50), a≠ − c ( m ) c ( m − 1 )

s + 1 + p + 1 + m eigenvalues

 

s + p + m + 1 eigenvalues

i.e. one extra eigenvalue 0

10

(3.28) and (3.50) with g = 0

(3.32) and (3.51)

 

z obeys (3.28) but not (3.50), a≠ − c ( m ) c ( m − 1 )

s + p + 1 + m eigenvalues

 

s + p + m + 1 eigenvalues

i.e. same eigenvalues

11

(3.28) and (3.50) with g = 0

(3.30) and (3.53)

 

z obeys (3.50) but not (3.28), a≠ − c ( m ) c ( m − 1 )

s + 1 + p + m eigenvalues

 

s + p + m + 1 eigenvalues

i.e. same eigenvalues

12

(3.28) and (3.50) with g = 0

(3.32) and (3.53)

 

z obeys both (3.28) and (3.50), a≠ − c ( m ) c ( m − 1 )

s + p + m eigenvalues

 

s + p + m + 1 eigenvalues

i.e. one less eigenvalue 0

13

(3.37) and (3.50) with g = 0

(3.38) and (3.51)

 

z does not obey (3.37) or (3.50)

s + p + 1 + m − 1 eigenvalues

 

s + p + m − 1 eigenvalues

i.e. one extra eigenvalue 0

14

(3.37) and (3.50) with g = 0

(3.39) and (3.51)

 

z obeys (3.37) but not (3.50)

s − 1 + p + 1 + m − 1 eigenvalues

 

s + p + m − 1 eigenvalues

i.e. same eigenvalues

15

(3.37) and (3.50) with g = 0

(3.38) and (3.53)

 

z obeys (3.50) but not (3.37)

s + p + m − 1 eigenvalues

 

s + p + m − 1 eigenvalues

i.e. same eigenvalues

16

(3.37) and (3.50) with g = 0

(3.39) and (3.53)

 

z obeys both (3.37) and (3.50)

s − 1 + p + m − 1 eigenvalues

 

s + p + m − 1 eigenvalues

i.e. one less eigenvalue 0