Let with the sup norm. Set , Let , the norm of is defined by
then is a Banach space. The cone is defined by
(3.1)
Let the nonnegative continuous concave functional α, the nonnegative continuous convex functionals β and γ, and the nonnegative continuous functional θ be defined on the cone P by
(3.2)
Since the first-order Δ-derivatives are involved in the nonlinear terms explicitly to the system (S), we give the following lemma.
Lemma 3.1 Assume (A
1) holds. If u = (u
1, u
2) ∈ P, then
where
Proof. In fact, it stuffices to prove that
holds. Suppose to contrary, there exists t
0 such that . Since u = (u
1, u
2) ∈ P, we choose that D such that , and is countable and contains no right-scattered elements of , u
i
(t) (i = 1, 2) is continuous on and differentiable in each t ∈ D, so u
i
(t) (i = 1, 2) is pre-differentiable with D. Let such that t
1 < t
0 < t
2, and the compact intervals such that U
1 has endpoints t
1, t
0, U
2 has endpoints t
0, σ(t
2).
For the endpoint t
1, from the mean value theorem on time scales [1, p25], one has that
u
i
(t) (i = 1, 2) is concave on , it follows that .
We have
so we have
For the endpoint σ(t
2), one has that
again, u
i
(t) (i = 1, 2) is concave on , it follows that . We have
we get
From the discussion results of the above cases, we can obtain that for t = t
0,
this is a contradiction. The proof is complete. □
To prove our main results, we recommend notation
where σ
2(t
2) = σ(σ(t
2)), and for i = 1, 2,
Theorem 3.2 Suppose (A
1)-(A
3) hold and f
i
(t, 0, 0, 0, 0) ≢ 0 (i = 1, 2) for . Assume that there exist positive numbers m
1, m
2 and m
4 such that m
1 < m
2 ≤
and
(C
1) if , v
1, v
2 ≥ 0, v
1 + v
2 ∈ [0, τ
2
m
4] and w
1 + w
2 ∈ [-m
4, m
4], then
;
(C
2) there exists i
0 ∈ {1, 2}, such that
for , v
l, v
2 ≥ 0, and w
1 + w
2 ∈ [-m
4, m
4];
(C
3) if , v
1, v
2 ≥ 0, v
1 + v
2 ∈ [0, m
1] and w
1 + w
2 ∈ [-m
4, m
4], then
Then the system (S) has at least three positive solutions u
1, u
2, and u
3 satisfying
(3.3)
Proof. Define the operator T by
where for . For u = (u
1, u
2) ∈ P, from Lemma 2.2 we note that the system (S) has a solution u if and only if u is the fixed point of u(t) = (Tu)(t). Hypothesis (A
3) implies that A(h
i
f
i
) ≥ 0, B(h
i
f
i
) ≥ 0 (i = 1, 2). By Equation 2.4, we have (T
i
)(t) ≥ 0 (i = 1, 2) for , (T
i
)(t) (i = 1, 2) is concave on and satisfies , , (i = 1, 2) Further we can obtain that , since for i = 1, 2,
on the other hand, for , Equation 2.2 implies that there exists τ
1 ∈ (0, 1) such that
Thus, we can conclude that Tu ∈ P. Furthermore, it is easy to check that the operator T is completely continuous by using Arzela-Ascoli lemma, and so the conditions of Lemma 2.1 hold with respect to T. α, γ, θ, and β are defined by Equation 3.2, we also note that α, γ, θ, β : P → [0, ∞) are continuous nonnegative functionals such that α(u) ≤ θ(u) = β(u) for all u ∈ P, β satisfies β(λu) ≤ λβ(u) for 0 ≤ λ ≤ 1, and |u| ≤ εγ (u) for all , where ε = max{τ
2, 1}. We now show that if assumption (C
1) is satisfied, then
(3.4)
In fact, for , we have . By Lemma 3.1, it holds , and so assumption (C
1) implies , for . On the other hand, for u ∈ P, we have proved that Tu = (T
1, T
2) ∈ P, it follows that
Thus,
Therefore, Equation 3.4 holds.
To check condition (B
1) in Lemma 2.1, we choose u
0 = (u
10, u
20), taking , . where . It is not difficult to verify that u
i 0(t) ≥ 0 (i = 1, 2), u
i 0(t) (i = 1, 2) is concave on and satisfies . By the properties of u
i 0(t) (i = 1, 2), we can obtain
(3.5)
(3.6)
Equations 3.5 and 3.6 imply that , thus we get u
0 ∈ P and so α(u
0) > m
2, θ(u
0) > m
2, γ(u
0) ≤ m
4 Further, and . For , there is for . Hence by assumption (C
2), one has that for . So we obtain that, for i
0 = 1, 2
Thus,
So we get α(Tu) > m
2 for and condition (B
1) in Lemma 2.1 is satisfied.
We now prove that condition (B
2) in Lemma 2.1 holds. In fact, if u = (u
1, u
2) ∈ P (γ, α, m
2, m
4) with , then
Finally, we assert that condition (B
3) in Lemma 2.1 also holds. (0, 0) ∉ Q(γ, β, m
1, m
4), since β((0, 0)) = 0 < m
1. Assume that u = (u
1, u
2) ∈ Q(γ, β, m
1, m
4) with β(u) = m
1, assumption (C
3) implies that