Throughout this section, we assume that is a unital multi--algebra, and and are multi-Banach left modules over . Moreover, by we denote the unitary group of .
Lemma 4.1 [7]
Let X and Y be vector spaces. An odd mapping satisfies (1.1) for all if and only if f is additive.
Corollary 4.2 [7]
Let X and Y be vector spaces. An odd mapping satisfies
if and only if f is additive.
Given a mapping , we set
for all and .
Theorem 4.3
Let
and
be an odd mapping such that for every
there is a function
with
for all and . If there exists an such that
for all and , then there is a unique -linear generalized additive mapping with
for all and .
Proof Put
and
for all . It is easy to show that is a complete generalized metric space.
Define a mapping by
Analysis similar to that in the proof of Theorem 3.1 in [8] (see also the proof of Lemma 3.2 in [12]) shows that
Fix . Putting , , and for in (4.2), we have
because f is odd and . We thus get
and therefore,
Consequently, by Theorem 2.2, there exists a mapping such that
-
(1)
is a fixed point of J, i.e.,
(4.5)
and is unique in the set
This means that is a unique mapping satisfying (4.5) such that there exists a with
for all and .
-
(2)
as . This implies the equality
(4.6)
-
(3)
, which together with (4.4) gives
and therefore, inequality (4.3) holds for all .
Next, note that the fact that the mapping f is odd and (4.6) imply that is odd. Moreover, by (4.1) and (4.2), we get
for all and , and therefore, is a generalized additive mapping.
Fix and . Using (4.1) and (4.2), we have
and consequently,
Since is a generalized additive mapping, from Lemma 4.1 it follows that is additive, and therefore,
As in the proof of Theorem 3.1, in [7] one can now show that is an -linear mapping. □
Corollary 4.4 Let and . Assume also that for , and for . If is an odd mapping such that
for all , , and , then there exists a unique -linear generalized additive mapping with
for all and .
Proof Putting and
for all and , in Theorem 4.3, we get the desired assertion. □
Theorem 4.5 Let . Let be an odd mapping for which there is a function such that
for all and all . If there exists an such that
for all . Then there exists a unique -linear generalized additive mapping such that
for all .
Proof Note that and for all since f is an odd mapping. Let . Putting and , in (4.7), we have
Letting , we get
for all .
The rest of the proof is similar to the proof of Theorem 4.3. □
Corollary 4.6 Let , and let θ and be positive real numbers, or let , and let θ and be positive real numbers. Let be an odd mapping such that
for all and all . Then there exists a unique -linear generalized additive mapping such that
for all .
Proof Define
Putting in Theorem 4.5, we get the desired result. □
Now we investigate the Hyers-Ulam stability of linear mappings for the case .
Theorem 4.7 Let . Let be an odd mapping for which there is a function such that
for all and all . If there exists an such that
for all . Then there exists a unique -linear generalized additive mapping such that
for all .
Proof Let . Putting in (4.8), we have
for all . So
for all .
The rest of the proof is the same as in the proof of Theorem 4.3. □
Corollary 4.8 Let , and let θ and be positive real numbers, or let , and let θ and be positive real numbers. Let be an odd mapping such that
for all and for all . Then there exists a unique -linear generalized additive mapping such that
for all .
Proof Define , and apply Theorem 4.7. Then we get the desired result. □
Theorem 4.9 Let . Let be an odd mapping for which there is a function such that
for all and all . If there exists an such that
for all . Then there exists a unique -linear generalized additive mapping such that
for all .
Proof Let . Putting in (4.9), we have
for all . So
for all .
The rest of the proof is similar to the proof of Theorem 4.3. □
Corollary 4.10 Let , and let θ and be positive real numbers. Or let , and let θ and be positive real numbers. Let be an odd mapping such that
for all and all . Then there exists a unique -linear generalized additive mapping such that
for all .
Proof Define , and apply Theorem 4.9. Then we get the desired result. □