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Solvability of a nonlocal boundary value problem for linear functional differential equations
Advances in Difference Equations volume 2013, Article number: 244 (2013)
Abstract
In the paper, the problem on the existence and uniqueness of a solution to the nonlocal problem
is considered, where and are linear bounded operators, , and .
MSC:34K06, 34K10.
1 Introduction and notation
On the interval , we consider the boundary value problem
where and are linear bounded operators, , and . By a solution to the equation (1), we understand an absolutely continuous function satisfying equality (1) almost everywhere on the interval . A solution to equation (1) satisfying the boundary condition (2) is said to be a solution to problem (1), (2).
The question on the solvability of various types of boundary value problems for functional differential equations and their systems is a classical topic in the theory of differential equations (see, e.g., [1–16] and references therein). There is a lot of interesting general results, but only a few efficient conditions are known, namely, in the case where a nonlocal boundary condition is considered. In the present paper, new efficient conditions are found sufficient for the unique solvability of problem (1), (2). An important particular case of the boundary condition (2) is
with , which in turn contains the initial condition (if ), the periodic condition (if ), and the anti-periodic condition (if ). Problem (1), (3) is studied, e.g., in [13, 17–19]. In [20, 21], the first step of our investigation in the general case was done. It is very useful to consider the boundary condition (2) as a nonlocal perturbation of the two-point condition (3). Therefore, we assume throughout the paper that the functional h is defined by the formula
where and . There is no loss of generality in assuming this, because an arbitrary functional h can be represented in form (4).
The paper is organized as follows. Main results are formulated and proved in Section 2. In Section 3, the main results are applied to the equation with argument deviations
where , , and are measurable functions. Some sufficient conditions for the validity of the inclusion , which are part of the conditions for the main results, are given in Section 4.
The following notation is used throughout the paper:
-
1.
ℝ is the set of all real numbers, .
-
2.
is the Banach space of continuous functions endowed with the norm .
-
3.
, where , is the set of absolutely continuous functions .
-
4.
is the Banach space of Lebesgue integrable functions endowed with the norm .
-
5.
, where .
-
6.
, where .
-
7.
is the set of linear bounded operators . is the set of operators , mapping the set into the set .
-
8.
is the set of linear bounded functionals . is the set of functionals mapping the set into the set .
-
9.
, where .
2 Main results
We assume throughout the paper that the following assumptions hold:
(H1) If , then the operator ℓ is supposed to be ‘nontrivial’ in the sense that the condition holds.
(H2) , where the functional is defined by the formula for .
Since we are interested in the unique solvability of problem (1), (2) for every q and c, both hypotheses (H1) and (H2) are rather natural. Indeed, if , then an arbitrary constant function is a solution to problem (1), (2) with and in the case, where . On the other hand, the assumption (H2) guarantees that the boundary condition (2) is not ‘degenerated.’
Before formulation of the main results, we introduce the following definitions.
Definition 2.1 [22]
Let . An operator is said to belong to the set , if every function , satisfying the relations
is nonpositive on the interval .
Definition 2.2 [23]
An operator is said to belong to the set (resp. ) if every function satisfying the relations
is nonnegative (resp. nonpositive) on the interval .
Remark 2.1 Efficient conditions, guaranteeing the validity of the inclusions and , , are stated, respectively, in [22] and [23].
2.1 Formulation of results
For the sake of transparency, we first formulate all the results; their proofs are postponed till Section 2.2 below.
Theorem 2.1 Assume that there exist operators and such that the inequality
holds on the set . If, moreover,
then problem (1), (2) has a unique solution.
Corollary 2.1 Let with and the relation hold. Moreover, there exists such that
Then problem (1), (2) has a unique solution.
Remark 2.2 Choosing a suitable number ε in Corollary 2.1 and using the results established in [22], we can obtain several efficient conditions, sufficient for the unique solvability of problem (1), (2). However, we do not formulate them in detail. We note only that for , the assumption (8) has the form
Theorem 2.2 Let there exist such that the inequality
holds on the set , where the functional ω is given by the formula
Then problem (1), (2) has a unique solution.
Theorem 2.3 Let with and the relations
be fulfilled. Moreover, there exists a function satisfying the conditions
where
Then problem (1), (2) has a unique solution.
Theorem 2.4 Let with and the relations
be fulfilled. Moreover, there exists a function such that condition (12) is satisfied and
where
Then problem (1), (2) has a unique solution.
Remark 2.3 The assumption appearing in Theorem 2.3 is not supposed in Theorem 2.4. On the other hand, assumption (17) of Theorem 2.4 is stronger than assumption (13) of Theorem 2.3.
Theorem 2.5 Let , the relations
hold, and there exists a function satisfying the conditions
Let, moreover, at least one of the following conditions be fulfilled
-
(a)
(23)
where the number is given by formula (15);
-
(b)
(24)
-
(c)
(25)
Then problem (1), (2) has a unique solution.
Remark 2.4 If the relation is fulfilled, then the assumption concerning the existence of a function γ in Theorem 2.5 can be omitted. Indeed, since the operator ℓ is supposed to be nontrivial in the case where , the function
satisfies conditions (21) and (22).
Remark 2.5 Define the operator by setting
Let
It is not difficult to verify that if u is a solution to problem (1), (2), then the function is a solution to the problem
and vice versa, if v is a solution to problem (26), then the function is a solution to problem (1), (2).
Using this transformation, we can immediately derive other conditions for the unique solvability of problem (1), (2), complementing those stated above. For example, Theorem 2.3 yields.
Theorem 2.3′ Let with and the relations
be fulfilled. Let, moreover, there exist a function satisfying the conditions
where
Then problem (1), (2) has a unique solution.
2.2 Proofs
The following lemma is well known from the general theory of boundary value problems for functional differential equations (see, e.g., [15, 24]; in the case, where the operator ℓ is strongly bounded, see also [1, 3, 14]).
Lemma 2.1 Problem (1), (2) is uniquely solvable if and only if the corresponding homogeneous problem
has only the trivial solution.
Remark 2.6 It follows immediately from Definition 2.1 and Lemma 2.1 that under the condition problem (1), (2) has a unique solution for every and .
Now, we are in position to prove the main results. According to Lemma 2.1, it is sufficient to show that the homogeneous problem (27), (28) has only the trivial solution.
Proof of Theorem 2.1 Let u be a solution to problem (27), (28). Then, in view of (6), we get
By virtue of the assumption and Remark 2.6, the problem
has a unique solution α. It follows from relations (29)-(31) that
On the other hand, conditions (28) and (32) yield
Therefore, by virtue of the assumption , relations (33) and (34) imply
Now, in view of (35) and the assumption , we get from (31) the relation
which, together with (7) and (32), yields that for . Consequently, condition (35) guarantees , and thus the homogeneous problem (27), (28) has only the trivial solution. □
Proof of Corollary 2.1 The validity of the corollary follows immediately from Theorem 2.1 with and . □
Proof of Theorem 2.2 Let u be a solution to problem (27), (28). Then, in view of (9), we get
On the other hand, by virtue of the assumptions , condition (28) yields
i.e.,
Taking now the assumption into account, we get from conditions (36) and (37) that
Consequently, the homogeneous problem (27), (28) has only the trivial solution. □
Proof of Theorem 2.3 Suppose that problem (27), (28) possesses a nontrivial solution u. According to conditions (11)-(13) and the assumption , Proposition 4.2 guarantees the validity of the inclusion
Therefore, by virtue of the assumption , it follows from Definition 2.1 that u changes its sign. Put
and choose such that
Obviously,
and without loss of generality, we can assume that . Using conditions (27), (28), (12), and (13), by virtue of (38), (40), and the assumption , we get
and
Hence, according to the condition , inequalities (41)-(44) yield
However, we assume that , and thus, it follows from (41) and (43) that
The integration of the first inequality in (45) from to , in view of (39) and (40), implies
i.e.,
On the other hand, the integrations of the second inequality in (45) from a to and from to b, in view of (39) and (40), yield
Moreover, on account of (38) and the assumptions , condition (28) results in
Therefore, from (47) we get
which, in view of (11) and (40), yields that
Now, from inequalities (46) and (48), we obtain
and
In view of the inequality , it follows from condition (50) that
which, together with (11) and (49), contradicts (14).
The contradiction obtained proves that problem (27), (28) has only the trivial solution. □
Proof of Theorem 2.4 Suppose that problem (27), (28) possesses a nontrivial solution u. According to conditions (12), (16), and (17) and the assumptions and , Proposition 4.2 guarantees the validity of the inclusion
where the functional is defined by the formula
Therefore, by virtue of the assumptions and , it follows from Definition 2.1 that u changes its sign. Define the numbers M and m by formulae (38), and choose such that conditions (39) hold. Obviously, (40) is satisfied, and without loss of generality, we can assume that . Using conditions (27), (28), (12), and (17), by virtue of (38), (40), (51), and the assumptions and , we get relations (41), (43),
and
Hence, according to the condition , inequalities (41), (43), (52), and (53) yield
However, we assume that , and thus, it follows from (41) and (43) that inequalities (45) hold.
Now, analogously to the proof of Theorem 2.3, relations (49) and (50) can be derived. Since assumption (16) implies , we get from (50) the inequality
which, together with (16) and (49), contradicts (18).
The contradiction obtained proves that problem (27), (28) has only the trivial solution. □
Proof of Theorem 2.5 Let u be a solution to problem (27), (28). We first show that each of assumptions (23), (24), or (25) ensures that u does not change its sign. Indeed, suppose that, on the contrary, u changes its sign. Define the numbers M and m by formulae (38), and choose such that conditions (39) hold. Obviously, (40) is satisfied, and without loss of generality, we can assume that .
-
(a)
Let condition (23) hold. Then the integrations of (27) from a to , from to , and from to b, in view of (38), (39), and the assumption , result in
(54)
Hence, by virtue of (40), condition (55) implies
On the other hand, on account of (38) and the assumptions , condition (28) yields
Now, combining (54) and (56), we get
which, on account of (20) and (40), yields
where . Now, conditions (57) and (58) yield
and
In view of the inequality , we get from condition (60) that
which, together with (20) and (59), contradicts (23).
-
(b)
If (24) holds then, in view of Definition 2.2, the assumption (resp. ) implies (resp. ) for , which contradicts (40).
-
(c)
If (25) holds, then, in view of Definition 2.2, the assumption (resp. ) implies (resp. ) for , which contradicts (40).
The contradictions obtained prove that u does not change its sign. We can assume without loss of generality, that the function u is nonnegative. Since , it follows from equation (27) that
Suppose that . Then, in view of (20), (61), and the assumptions , condition (28) yields
Hence, condition (61) implies
Put
where
According to (62), it is clear that
and there exists such that
Taking now (27), (21), (63), and the assumption into account, we obtain
Therefore, on account of conditions (63) and (64), the latter relation yields
However, using (28), (20), (22), (65), and the assumptions , we get the contradiction
The contradiction obtained proves that , and thus, condition (61) implies . Consequently, the homogeneous problem (27), (28) has only the trivial solution. □
3 Differential equations with argument deviations
In this section, we give some corollaries of the main results for the equation with deviating arguments (5). Recall that we suppose that and are measurable functions. The conditions stated below show that problem (5), (2) is uniquely solvable, provided that either the coefficients p and g are ‘small’ in a certain sense, or the deviations τ and μ are ‘close’ to the identities (the functional differential equation (5) is ‘close’ to the ordinary one).
3.1 Formulation of results
Theorem 2.1 implies the following.
Corollary 3.1 Let relations (11) be fulfilled, and let the functions p and τ satisfy at least one of the following conditions:
-
(a)
-
(b)
, for a.e. , and
(66)
where
Let, moreover, the functions g and μ satisfy at least one of the following conditions:
-
(A)
(67)
-
(B)
and
(68)
where
Then problem (5), (2) has a unique solution.
From Theorem 2.3, we derive
Corollary 3.2 Let relations (11) be fulfilled and
where the number is given by formula (15) and
and
Then problem (5), (2) has a unique solution.
Theorem 2.4 yields the following.
Corollary 3.3 Let relations (16) be fulfilled,
and
where the functions , , , and σ are defined by formulae (73)-(76), the number is given by formula (19), and
Then problem (5), (2) has a unique solution.
Finally, we give statements concerning equation (5) with , i.e., the equation
where , , and is a measurable function.
From Theorem 2.1 we can derive the following.
Corollary 3.4 Let relations (11) be fulfilled,
and
where
Then problem (80), (2) has a unique solution.
The next two statements follow from Theorem 2.5.
Corollary 3.5 Let , let the relations
be fulfilled, and let
where
Let, moreover,
where
Then problem (80), (2) has a unique solution.
Corollary 3.6 Let , let the relations
be fulfilled, and let condition (85) hold, where the number is defined by formula (86). Then problem (80), (2) has a unique solution.
3.2 Proofs
Proof of Corollary 3.1 Let the operators and be defined by the formulae
and
It is easy to verify that both conditions (a) and (b) of the corollary yield
(see Propositions 4.3 and 4.4).
On the other hand, both conditions (A) and (B) of the corollary guarantee the validity of the inclusion
(see Propositions 4.5 and 4.6).
Consequently, the assumptions of Corollary 2.1 are satisfied with . □
Proof of Corollary 3.2 Let the operators and be defined by formulae (87) and (88), respectively. According to condition (71), there exists such that
Moreover, conditions (11), (70), and (71) imply . Therefore, by virtue of (70) and (72), Proposition 4.7 guarantees the validity of the inclusion
Hence, according to Remark 2.6, the problem
has a unique solution γ. It is clear that the function γ satisfies conditions (12) and (13). Using the inclusion , we get for , and thus, equation (90) yields
Furthermore, on account of (11), (92), and the assumptions , condition (91) implies
Therefore, condition (92) yields that for .
On the other hand, γ is a solution to the equation
Hence, in view of notations (73) and (75), the Cauchy formula implies
for , whence we get
Taking now conditions (92), (93) and the assumptions into account, the relation (91) yields
Therefore, we get from (93) and (94) the inequality
On the other hand, by virtue of (92) and the assumptions , condition (91) implies
and thus,
Now, it is clear that conditions (89), (95), and (96) guarantee the validity of inequality (14).
Consequently, the assumptions of Theorem 2.3 are satisfied. □
Proof of Corollary 3.3 Let the operators and be defined by formulae (87) and (88), respectively. Condition (78) implies . Therefore, according to (77) and (79), Proposition 4.7 guarantees the validity of the inclusion
where the functional is defined by formula (51). Hence, by virtue of Remark 2.6, equation (90) has a unique solution γ satisfying the boundary condition
It is clear that the function γ satisfies conditions (12) and (17). Using inclusion (97), we get for , and thus, equation (90) yields the relation (92). Moreover, on account of (16), (92) and the assumption , condition (98) implies
Therefore, condition (92) yields that for .
On the other hand, γ is a solution to the equation
Hence, in view of notations (73) and (75), the Cauchy formula implies
for , whence we get relation (93). Taking now (93) and the assumption into account, condition (98) yields
Therefore, we get from (93) and (99) the inequality
On the other hand, by virtue of (92) and the assumption , condition (98) implies
and thus,
Now it is clear that conditions (78), (100), and (101) guarantee the validity of inequality (18).
Consequently, the assumptions of Theorem 2.4 are satisfied. □
Proof of Corollary 3.4 Let the operator be defined by formula (87), and let . It is easy to verify that conditions (81) and (82) yield
(see Propositions 4.3 and 4.6).
Consequently, assumptions of Corollary 2.1 are satisfied with . □
Proof of Corollary 3.5 Let the operator ℓ be defined by the formula
It is clear that . Moreover, condition (85) implies the validity of inclusion (24) (see Proposition 4.8).
On the other hand, according to (83) and (84), there exist and such that
and
where
Obviously, condition (103) yields . Therefore, we get from (104) the relation
Now, we put
Then, by virtue of (105), (106), and the assumptions , it is easy to verify that the function γ satisfies conditions (21) and (22).
Consequently, the assumptions of Theorem 2.5 are fulfilled. □
Proof of Corollary 3.6 Let the operator ℓ be defined by formula (102). It is clear that . Moreover, condition (85) implies the validity of inclusion (24) (see Proposition 4.8).
Consequently, by virtue of Remark 2.4, the assumptions of Theorem 2.5 are satisfied. □
4 On the set
In this section, we give some sufficient conditions guaranteeing the inclusions , , and , which are stated in [22, 23]. We first formulate rather general results.
Proposition 4.1 [[22], Cor. 4.1]
Let be a b-Volterra operator, and let the functional h be defined by formula (4), where and are such that inequalities (11) are fulfilled. If there exists a function satisfying
then .
Proposition 4.2 [[22], Thms. 3.2 and 4.3]
Let , and let the functional h be defined by formula (4), where and are such that inequalities (11) are fulfilled. Then if and only if there exists a function satisfying
Choosing suitable functions γ in the propositions stated above, we can derive several efficient conditions sufficient for the validity of the inclusion . These conditions are not formulated here in detail; we present, however, some of their corollaries for ‘operators with argument deviations,’ which are used in the proofs of the results stated in Section 3.
Proposition 4.3 [[22], Cor. 5.3]
Let , be a measurable function, and let the functional h be defined by formula (4), where and are such that inequalities (11) are fulfilled. If
then the operator ℓ, defined by formula (102), belongs to the set .
Proposition 4.4 [[22], Thm. 5.3(c)]
Let , be a measurable function, and let the functional h be defined by formula (4), where and are such that the inequalities
are fulfilled. Assume that for a.e. , and inequality (66) holds, where
Then the operator ℓ, defined by formula (102), belongs to the set .
Proposition 4.5 [[22], Rem. 4.3]
Let , be a measurable function, and let the functional h be defined by formula (4), where and are such that inequalities (11) are fulfilled. If, moreover, inequality (67) is satisfied, then the operator ℓ, defined by the formula
belongs to the set .
Proposition 4.6 [[22], Cor. 5.2]
Let , be a measurable function, and let the functional h be defined by formula (4), where and are such that inequalities (11) are fulfilled. If, moreover, and inequality (68) is satisfied, where the number is given by formula (69), then the operator ℓ, defined by formula (107), belongs to the set .
Proposition 4.7 [[22], Thm. 5.7]
Let , be a measurable function, and let the functional h be defined by formula (4), where and are such that inequalities (11) are fulfilled. If, moreover, inequalities (70) and
are satisfied, where the functions and are defined by formulae (73), (74), and (76), then the operator ℓ, defined by formula (107), belongs to the set .
The last statement concerns the set .
Proposition 4.8 [[23], Thm. 1.9]
Let , , be such that inequality (85) is satisfied, where the number is defined by formula (86). Then the operator ℓ, defined by formula (102), belongs to the set .
Author’s contributions
The author read and approved the final manuscript.
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Acknowledgements
Published results were supported by the project Popularization of BUT R&D results and support systematic collaboration with Czech students CZ.1.07/2.3.00/35.0004 and by Grant No. FSI-S-11-3 ‘Modern methods of mathematical problem modelling in engineering.’
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Opluštil, Z. Solvability of a nonlocal boundary value problem for linear functional differential equations. Adv Differ Equ 2013, 244 (2013). https://doi.org/10.1186/1687-1847-2013-244
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DOI: https://doi.org/10.1186/1687-1847-2013-244