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Theory and Modern Applications

Global existence of solutions for interval-valued second-order differential equations under generalized Hukuhara derivative

Abstract

In this paper, we present a generalized concept of second-order differentiability for interval-valued functions. The global existence of solutions for interval-valued second-order differential equations (ISDEs) under generalized H-differentiability is proved. We present some examples of linear interval-valued second-order differential equations with initial conditions having four different solutions. Finally, we propose a new algorithm based on the analysis of a crisp solution. Some examples are given by using our proposed algorithm.

MSC:34K05, 34K30, 47G20.

1 Introduction

The set-valued differential and integral equations are an important part of the theory of set-valued analysis. They have the important value of theory and application in control theory; and they were studied in 1969 by De Blasi and Iervolino [1]. Recently, set-valued differential equations have been studied by many authors due to their application in many areas. For the basic theory on set-valued differential and integral equations, the readers can be referred to the good books and papers [210] and references therein. The interval-valued analysis and interval differential equations (IDEs) are the particular cases of the set-valued analysis and set differential equations, respectively. In many cases, when modeling real-world phenomena, information about the behavior of a dynamic system is uncertain, and we have to consider these uncertainties to gain more models. Interval-valued differential and integro-differential equations are a natural way to model dynamic systems subject to uncertainties. Recently, many works have been done by several authors in the theory of interval-valued differential equations (see, e.g., [1115]). There are several approaches to the study of interval differential equations. One popular approach is based on H-differentiability. The approach based on H-derivative has the disadvantage that it leads to solutions which have an increasing length of their support. Note that this definition of derivative is very restrictive; for instance, we can see that if X(t)=Ax(t), where A is an interval-valued constant and x:[a,b] R + is a real function with x (t)<0, then X(t) is not differentiable. Recently, to avoid this difficulty, Stefanini and Bede [12] solved the above mentioned approach under strongly generalized differentiability of interval-valued functions. In this case, the derivative exists and the solution of an interval-valued differential equation may have decreasing length of the support, but the uniqueness is lost. The paper of Stefanini and Bede was a starting point for the topic of interval-valued differential equations (see [1416]) and later also for fuzzy differential equations.

The connection between the fuzzy analysis and the interval analysis is very well known (Moore and Lodwick [17]). Interval analysis and fuzzy analysis were introduced as an attempt to handle interval uncertainty that appears in many mathematical or computer models of some deterministic real-world phenomena. In [18] authors considered n th-order fuzzy differential equations with initial value conditions and proved the local existence and uniqueness of solution for nonlinearities satisfying a Lipschitz condition. In [12, 19] authors studied the existence of the solutions to interval-valued and fuzzy differential equations involving generalized differentiability. Based on the results in [18], authors studied the local existence and uniqueness of solutions for fuzzy second-order integro-differential equations with fuzzy kernel under strongly generalized H-differentiability [20]. In [21]n th-order fuzzy differential equations (NFDEs) under generalized differentiability were discussed and the existence and uniqueness theorem of solution of NFDE was proved by using the contraction principle in a Banach space. In [22] authors developed the fuzzy improved Runge-Kutta-Nystrom method for solving a second-order fuzzy differential based on the generalized concept of higher-order fuzzy differentiability. Also, a very important generalization and development related to the subject of the present paper is in the field of fuzzy sets, i.e., fuzzy calculus and fuzzy differential equations under the generalized Hukuhara derivative. Recently, several works, e.g., [13, 2343], have been done on set-valued differential equations, fuzzy differential equations, and fuzzy integro-differential equations, fractional fuzzy differential equations, and some methods for solving fuzzy differential equations [4449].

In [12, 14, 15] the authors presented interval-valued differential equations under generalized Hukuhara differentiability which were given in the following form:

D H 1 , g X(t)=F ( t , X ( t ) ) ,X( t 0 )= X 0 K C (R),t[ t 0 , t 0 +p],
(1.1)

where D H 1 , g denotes two kinds of derivatives, namely the classical Hukuhara derivative and the second type Hukuhara derivative (generalized Hukuhara differentiability). The existence and uniqueness of a Cauchy problem is then obtained under an assumption that the coefficients satisfy a condition with the Lipschitz constant (see [12]). The proof is based on the application of the Banach fixed point theorem. In [15], under the generalized Lipschitz condition, Malinowski obtained the existence and uniqueness of solutions to both kinds of IDEs.

In this paper, we study four kinds of solutions to ISDEs

D H 2 , g X ( t ) = F ( t , X ( t ) , D H 1 , g X ( t ) ) , X ( t 0 ) = I 1 , D H 1 , g X ( t 0 ) = I 2 K C ( R ) , t [ t 0 , T ] .
(1.2)

The different types of solutions to ISDEs are generated by the usage of two different concepts of interval-valued second-order derivative. This direction of research is motivated by the results of Stefanini and Bede [12], Malinowski [14, 15] concerning deterministic IDEs with generalized interval-valued derivative.

This paper is organized as follows. In Section 2, we recall some basic concepts and notations about interval analysis and interval-valued differential equations. In Section 3, we present the global existence and uniqueness theorem of a solution to the interval-valued second-order differential equation under two kinds of the Hukuhara derivative. Some examples of linear second-order interval-valued differential equations with initial conditions having four different solutions are presented. In Section 4, we propose a new algorithm based on the analysis of a crisp solution.

2 Preliminaries

Let K C (R) denote the family all nonempty, compact and convex subsets of . The addition and scalar multiplication in K C (R), we define as usual, i.e., for A,B K C (R), A=[ A ̲ , A ¯ ], B=[ B ̲ , B ¯ ], where A ̲ A ¯ , B ̲ B ¯ and λ0, then we have

A+B=[ A ̲ + B ̲ , A ¯ + B ¯ ],λA=[λ A ̲ ,λ A ¯ ] ( λ A = [ λ A ¯ , λ A ̲ ] ) .

Furthermore, let A K C (R), λ 1 , λ 2 , λ 3 , λ 4 R and λ 3 λ 4 0, then we have λ 1 ( λ 2 A)=( λ 1 λ 2 )A and ( λ 3 + λ 4 )A= λ 3 A+ λ 4 A. Let A,B K C (R) as above. Then the Hausdorff metric H in K C (R) is defined as follows:

H(A,B)=max { | A ̲ B ̲ | , | A ¯ B ¯ | } .
(2.1)

We notice that ( K C (R),H) is a complete, separable and locally compact metric space.

We define the magnitude and length of A K C (R) by

H ( A , { 0 } ) =A=max { | A ̲ | , | A ¯ | } ,len(A)= A ¯ A ̲ ,

respectively, where {0} is the zero element of K C (R), which is regarded as one point.

The Hausdorff metric (2.1) satisfies the following properties:

H ( A + C , B + C ) = H ( A , B ) and H ( A , B ) = H ( B , A ) , H ( A + B , C + D ) H ( A , C ) + H ( B , D ) , H ( λ A , λ B ) = | λ | H ( A , B ) , H ( A , B ) H ( A , C ) + H ( C , B )

for all A,B,C,D K C (R) and λR. Let A,B K C (R). If there exists an interval C K C (R) such that A=B+C, then we call C the Hukuhara difference of A and B. We denote the interval C by AB. Note that ABA+()B. It is known that AB exists in the case len(A)len(B). Besides that, we can see [14] the following properties for A,B,C,D K C (R):

  • If AB, AC exist, then H(AB,AC)=H(B,C);

  • If AB, CD exist, then H(AB,CD)=H(A+D,B+C);

  • If AB, A(B+C) exist, then there exist (AB)C and (AB)C=A(B+C);

  • If AB, AC, CB exist, then there exist (AB)(AC) and (AB)(AC)=CB.

Definition 2.1 We say that the interval-valued mapping F:[a,b] R + K C (R) is continuous at the point t[a,b] if for every ε>0 there exists δ=δ(t,ε)>0 such that, for all s[a,b] such that |ts|<δ, one has H(F(t),F(s))ε.

The strongly generalized differentiability was introduced in [12] and studied in [14, 3840].

Definition 2.2 Let X:[a,b] K C (R) and t[a,b]. We say that X is strongly generalized differentiable of the first-order differential at t if there exists D H 1 , g X(t) K C (R) such that

  1. (i)

    for all h>0 sufficiently small, X(t+h)X(t), X(t)X(th) and

    lim h 0 H ( X ( t + h ) X ( t ) h , D H 1 , g X ( t ) ) = 0 , lim h 0 H ( X ( t ) X ( t h ) h , D H 1 , g X ( t ) ) = 0 ,

or

  1. (ii)

    for all h>0 sufficiently small, X(t)X(t+h), X(th)X(t) and

    lim h 0 H ( X ( t ) X ( t + h ) h , D H 1 , g X ( t ) ) = 0 , lim h 0 H ( X ( t h ) X ( t ) h , D H 1 , g X ( t ) ) = 0 ,

or

  1. (iii)

    for all h>0 sufficiently small, X(t+h)X(t), X(th)X(t) and

    lim h 0 H ( X ( t + h ) X ( t ) h , D H 1 , g X ( t ) ) = 0 , lim h 0 H ( X ( t h ) X ( t ) h , D H 1 , g X ( t ) ) = 0 ,

or

  1. (iv)

    for all h>0 sufficiently small, X(t)X(t+h), X(t)X(th) and the limits

    lim h 0 H ( X ( t ) X ( t + h ) h , D H 1 , g X ( t ) ) = 0 , lim h 0 H ( X ( t ) X ( t h ) h , D H 1 , g X ( t ) ) = 0

(h at denominators means 1 h ). In this definition, case (i) ((i)-differentiability for short) corresponds to the classical H-derivative, so this differentiability concept is a generalization of the Hukuhara derivative.

Lemma 2.1 [12, 14, 15]

The interval-valued differential equation D H 1 , g X(t)=F(t,X(t)), X(a)= X 0 K C (R), where F:[a,b]× K C (R) K C (R) is supposed to be continuous, is equivalent to one of the integral equations

X ( t ) = X 0 + a t F ( s , X ( s ) ) d s , t [ a , b ] or X ( a ) = X ( t ) + ( 1 ) a t F ( s , X ( s ) ) d s , t [ a , b ]

on the interval [a,b]R, under the strong differentiability condition, (i) or (ii), respectively. We notice that the equivalence between two equations in this lemma means that any solution is a solution for the other one.

Definition 2.3 Let X:[a,b] K C (R) and t[a,b]. We say that X is strongly generalized differentiable of the second-order differential at t if there exists D H 2 , g X(t) K C (R) such that

  1. (i)

    for all h>0 sufficiently small, D H 1 , g X(t+h) D H 1 , g X(t), D H 1 , g X(t) D H 1 , g X(th) and the following limits hold (in the metric H)

    lim h 0 D H 1 , g X ( t + h ) D H 1 , g X ( t ) h = lim h 0 D H 1 , g X ( t ) D H 1 , g X ( t h ) h = D H 2 , g X(t),

or

  1. (ii)

    for all h>0 sufficiently small, D H 1 , g X(t) D H 1 , g X(t+h), D H 1 , g X(th) D H 1 , g X(t) and the following limits hold (in the metric H)

    lim h 0 D H 1 , g X ( t ) D H 1 , g X ( t + h ) h = lim h 0 D H 1 , g X ( t h ) D H 1 , g X ( t ) h = D H 2 , g X(t),

or

  1. (iii)

    for all h>0 sufficiently small, D H 1 , g X(t+h) D H 1 , g X(t), D H 1 , g X(th) D H 1 , g X(t) and the following limits hold (in the metric H)

    lim h 0 D H 1 , g X ( t + h ) D H 1 , g X ( t ) h = lim h 0 D H 1 , g X ( t h ) D H 1 , g X ( t ) h = D H 2 , g X(t),

or

  1. (iv)

    for all h>0 sufficiently small, D H 1 , g X(t) D H 1 , g X(t+h), D H 1 , g X(t) D H 1 , g X(th) and the following limits hold (in the metric H)

    lim h 0 D H 1 , g X ( t ) D H 1 , g X ( t + h ) h = lim h 0 D H 1 , g X ( t ) D H 1 , g X ( t h ) h = D H 2 , g X(t).

In this paper we consider only the two first items of Definition 2.3. In the other cases, the derivative is trivial because it is reduced to a crisp element. Let us consider the interval-valued second differential equation initial value problem (ISDE) of the form

D H 2 , g X(t)=F ( t , X ( t ) , D H 1 , g X ( t ) ) ,X( t 0 )= I 1 , D H 2 , g X( t 0 )= I 2 ,t[ t 0 ,T],
(2.2)

where X(t)=[ X ̲ (t), X ¯ (t)] is an interval-valued function of t, F(t,X(t), D H 1 , g X(t)) is an interval-valued function and the interval-valued variables D H 1 , g X(t), D H 2 , g X(t) are defined as the derivatives of X(t) and D H 1 , g X(t), respectively.

Theorem 2.1 Let X:[ t 0 ,T] K C (R) and D H 1 , g X:[ t 0 ,T] K C (R) be interval-valued functions, where X(t)=[ X ̲ (t), X ¯ (t)]. If X, D H 1 , g X are (i)-differentiable or (ii)-differentiable, then X ̲ (t), X ¯ (t) and ( X ̲ ( t ) ) , ( X ¯ ( t ) ) are differentiable functions and

  1. (i)

    D H 2 , g X(t)=[ ( X ̲ ( t ) ) , ( X ¯ ( t ) ) ], where X and D H 1 , g X are (i)-differentiable;

  2. (ii)

    D H 2 , g X(t)=[ ( X ¯ ( t ) ) , ( X ̲ ( t ) ) ], where X is (i)-differentiable and D H 1 , g X is (ii)-differentiable;

  3. (iii)

    D H 2 , g X(t)=[ ( X ¯ ( t ) ) , ( X ̲ ( t ) ) ], where X is (ii)-differentiable and D H 1 , g X is (i)-differentiable;

  4. (iv)

    D H 2 , g X(t)=[ ( X ̲ ( t ) ) , ( X ¯ ( t ) ) ], where X and D H 1 , g X are (i)-differentiable.

Definition 2.4 Let X:[ t 0 ,T] K C (R) and D H 1 , g X:[ t 0 ,T] K C (R), we define:

  1. (a)

    The space of continuous functions X by C([ t 0 ,T], K C (R)) with the distance

    H 0 (X,Y)= sup t [ t 0 , T ] { H ( X , Y ) exp ( k t ) } ;
    (2.3)
  2. (b)

    The space of continuous functions D H 1 , g X(t) by C 1 ([ t 0 ,T], K C (R)) with the distance

    H 0 1 (X,Y)= H 0 (X,Y)+ H 0 ( D H 1 , g X , D H 1 , g Y ) ,
    (2.4)

where we assume that D H 1 , g X, D H 1 , g Y exist and k R + .

In this definition, we know that the space (C([ t 0 ,T], K C (R)), H 0 ) of continuous functions X:[ t 0 ,T] K C (R) is a complete metric space with distance (2.3).

Lemma 2.2 ( C 1 ([ t 0 ,T], K C (R)), H 0 1 ) is a complete metric space.

Based on Definition 2.3, there are two possible cases for each derivation, so there are four possible cases for the second-order derivation.

Theorem 2.2 Assume that F:[ t 0 ,T]× K C (R)× K C (R) K C (R) is continuous. A mapping X:[ t 0 ,T] K C C (R) is a solution to problem (2.2) if and only if X and D H 1 , g X(t) are continuous on [ t 0 ,T] and satisfy one of the following interval integral equations:

  1. (i)

    X(t)= I 1 + I 2 (t t 0 )+ t 0 t ( t 0 t F(s,X(s), D H 1 , g X(s))ds)ds, where D H 1 , g X(t) and D H 2 , g X(t) are (i)-differentials, or

  2. (ii)

    X(t)= I 1 (1)( I 2 (t t 0 )+ t 0 t ( t 0 t F(s,X(s), D H 1 , g X(s))ds)ds), where D H 1 , g X(t) is (i)-differential and D H 2 , g X(t) is (ii)-differential, or

  3. (iii)

    X(t)= I 1 + I 2 (t t 0 )(1) t 0 t ( t 0 t F(s,X(s), D H 1 , g X(s))ds)ds, where D H 1 , g X(t) is (ii)-differential and D H 2 , g X(t) is (i)-differential, or

  4. (iv)

    X(t)= I 1 ( I 2 (t t 0 )(1) t 0 t ( t 0 t F(s,X(s), D H 1 , g X(s))ds)ds), where D H 1 , g X(t) and D H 2 , g X(t) are (ii)-differentials.

Definition 2.5 Let X:[ t 0 ,T] K C (R), D H 1 , g X:[ t 0 ,T] K C (R) be interval-valued functions which are (i)-differentiable. If X, D H 1 , g X and their derivatives satisfy problem (2.2), we say X is a (i-i)-solution of problem (2.2).

Definition 2.6 Let X:[ t 0 ,T] K C (R), D H 1 , g X:[ t 0 ,T] K C (R) be interval-valued functions which are (i)-differentiable and (ii)-differentiable, respectively. If X, D H 1 , g X and their derivatives satisfy problem (2.2), we say X is a (i-ii)-solution of problem (2.2).

Definition 2.7 Let X:[ t 0 ,T] K C (R), D H 1 , g X:[ t 0 ,T] K C (R) be interval-valued functions which are (ii)-differentiable and (i)-differentiable, respectively. If X, D H 1 , g X and their derivatives satisfy problem (2.2), we say X is a (ii-i)-solution of problem (2.2).

Definition 2.8 Let X:[ t 0 ,T] K C (R), D H 1 , g X:[ t 0 ,T] K C (R) be interval-valued functions which are (ii)-differentiable. If X, D H 1 , g X and their derivatives satisfy problem (2.2), we say X is a (ii-ii)-solution of problem (2.2).

Theorem 2.3 Let F:[ t 0 ,T]× K C (R)× K C (R) K C (R) be continuous, and suppose that there exist L 1 , L 2 R+ such that

H ( F ( t , X 1 , Y 1 ) , F ( t , X 2 , Y 2 ) ) L 1 H( X 1 , X 2 )+ L 2 H( Y 1 , Y 2 )

for all t[ t 0 ,T], X 1 , X 2 , Y 1 , Y 2 K C (R). Then problem (2.2) has a unique local solution on some intervals [ t 0 ,T] (TT t 0 ) for each case.

3 Global existence of solutions for interval-valued second-order differential equations

In this section of the paper, we shall consider again the following initial value problem for the interval-valued second-order differential equation (ISDE) of the form

D H 2 , g X(t)=F ( t , X ( t ) , D H 1 , g X ( t ) ) ,X( t 0 )= I 1 , D H 1 , g X( t 0 )= I 2
(3.1)

for all tI=[ t 0 ,), where F:I× K C (R)× K C (R) K C (R).

Theorem 3.1 Assume that

(C1) F(,,):I× K C (R)× K C (R) K C (R) is locally Lipschitzian in X, D H 1 , g X(t);

(C2) H(F(t,X, D H 1 , g X(t)),{0})g(t,H(X,{0}),H( D H 1 , g X(t),{0})), for all (t,X, D H 1 , g X(t))I× K C (R)× K C (R), where gC[I× R + × R + , R + ] is a nondecreasing function for each tI, and the maximal solution r(t, t 0 , u 0 , u 0 ) of the scalar initial value problem

d 2 d t u(t)=g ( t , u , u ) ,u( t 0 )= u 0 , u ( t 0 )= u 0 ,
(3.2)

exists throughout I;

(C3) H(X(t, t 0 , X 0 , D H 1 , g X( t 0 )),{0})r(t, t 0 , u 0 , u 0 ), H( X 0 ,{0}) u 0 and H( D H 1 , g X( t 0 ),{0}) u 0 .

Then the largest interval of the existence of any solution X(t, t 0 , X 0 , D H 1 , g X( t 0 )) of (3.1) for each case is I. In addition, if r(t, t 0 , u 0 , u 0 ) is bounded on I, then lim t X(t, t 0 , X 0 , D H 1 , g X( t 0 )) exists.

Proof Since the way of the proof is similar for four cases, we only prove the case X and D H 1 , g X are (i)-differentiable. By hypothesis (C1), there exists T> t 0 such that the unique solution of problem (3.1) exists on I. Let S={X(t)|X(t) is defined on [ t 0 , β X ] and is the solution to (3.1)}. Then S. Taking β=sup{ β X |X(t)S}, clearly, there exists a unique solution of (3.1) which is defined on [ t 0 ,β) with H( X 0 ,{0}) u 0 and H( D H 1 , g X( t 0 ),{0}) u 0 . If β=, obviously, the theorem is proved. Hence we suppose β< and define m(t)=H(X(t, t 0 , X 0 , D H 1 , g X( t 0 )),{0}), t 0 t<β. Then we have

D + m ( t ) = lim h 0 + inf ( H ( D H 1 , g X ( t + h , t 0 , X 0 , D H 1 , g X ( t 0 ) ) , { 0 } ) h D + m ( t ) = H ( D H 1 , g X ( t , t 0 , X 0 , D H 1 , g X ( t 0 ) ) , { 0 } ) h ) D + m ( t ) lim h 0 + inf H ( D H 1 , g X ( t + h , t 0 , X 0 , D H 1 , g X ( t 0 ) ) , D H 1 , g X ( t , t 0 , X 0 , D H 1 , g X ( t 0 ) ) ) h D + m ( t ) = lim h 0 + inf H ( D H 1 , g X ( t + h , t 0 , X 0 , D H 1 , g X ( t 0 ) ) D H 1 , g X ( t , t 0 , X 0 , D H 1 , g X ( t 0 ) ) h , { 0 } ) D + m ( t ) = H ( F ( t , X ( t , t 0 , X 0 , D H 1 , g X ( t 0 ) ) , D H 1 , g X ( t , t 0 , X 0 , D H 1 , g X ( t 0 ) ) ) , { 0 } ) D + m ( t ) g ( t , m ( t ) , m ( t ) )

for all t 0 t<β and m( t 0 )=H( X 0 ,{0}) u 0 . Further, by assumption (C3), it follows that m(t)r(t, t 0 , u 0 , u 0 ). Now, we show that lim t X(t, t 0 , X 0 , D H 1 , g X( t 0 )) exists. In fact, for any t 1 , t 2 such that t 0 t 1 < t 2 <β, we have

H ( X ( t 1 , t 0 , X 0 , D H 1 , g X ( t 0 ) ) , X ( t 2 , t 0 , X 0 , D H 1 , g X ( t 0 ) ) ) = H ( I 1 + ( I 2 ( t 1 t 0 ) + t 0 t 1 ( t 0 s F ( τ , X ( τ ) , D H 1 , g X ( τ ) ) d τ ) d s ) , I 1 + ( I 2 ( t 2 t 0 ) + t 0 t 2 ( t 0 s F ( τ , X ( τ ) , D H 1 , g X ( τ ) ) d τ ) d s ) ) H ( t 0 t 1 ( t 0 s F ( τ , X ( τ ) , D H 1 , g X ( τ ) ) d τ ) d s , t 0 t 2 ( t 0 s F ( τ , X ( τ ) , D H 1 , g X ( τ ) ) d τ ) d s ) t 1 t 2 ( t 0 s H ( F ( τ , X ( τ ) , D H 1 , g X ( τ ) ) , { 0 } ) d τ ) d s r ( t 2 , t 0 , u 0 , u 0 ) r ( t 1 , t 0 , u 0 , u 0 ) .

Since lim t β 0 r(t) exists and is finite, taking the limits as t 1 , t 2 β0 and using the completeness of ( K C (R),H) in the last inequality, we see that lim t β 0 X(t, t 0 , X 0 , D H 1 , g X( t 0 )) exists in ( K C (R),H). Define X(β)= lim t β 0 X(t, t 0 , X 0 , D H 1 , g X( t 0 )) and consider the IVP

D H 2 , g X(t)=F ( t , X , D H 1 , g X ( t ) ) ,X(β)= lim t β 0 X(t).

Therefore X(t) can be extended beyond β, which contradicts our assumption. In addition, since r(t, t 0 , u 0 , u 0 ) is bounded and nondecreasing on I, it follows that lim t X(t, t 0 , X 0 , D H 1 , g X( t 0 )) exists and is finite. □

Example 3.2 Consider the linear second-order IDE

D H 2 , g X(t)=A(t) D H 1 , g X(t)+B(t)X(t),X( t 0 )= I 1 , D H 1 , g X( t 0 )= I 2 ,
(3.3)

where we assume that A(),B(): R + R + are continuous functions, then the solutions of (3.3) for each case are on [ t 0 ,).

We see that F(t,X, D H 1 , g X(t))=A(t) D H 1 , g X(t)+B(t)X(t) is locally Lipschitzian. If we let g(t,u, u )=A(t) u +B(t)u, then u(t)0 is a unique solution of second-order initial differential equation as follows:

u (t)=A(t) u (t)+B(t)u(t),u( t 0 )=0, u ( t 0 )=0,
(3.4)

on [ t 0 ,). In the other hand, we have

H ( F ( t , X , D H 1 , g X ( t ) ) , { 0 } ) = H ( A ( t ) D H 1 , g X ( t ) + B ( t ) X ( t ) , { 0 } ) B ( t ) H ( X , { 0 } ) + A ( t ) H ( D H 1 , g X ( t ) , { 0 } ) = g ( t , H ( X , { 0 } ) , H ( D H 1 , g X ( t ) , { 0 } ) ) .

Therefore, the solutions of Example 3.2 are on [ t 0 ,).

Theorem 3.3 Assume that

(C4) FC[I× K C (R)× K C (R)], F is bounded on bounded sets, and there exists a local solution of problem (3.1) for every ( t 0 , X 0 , D H 1 , g X( t 0 ))I× K C (R)× K C (R);

(C5) VC[I× K C (R)× K C (R), R + ], V is locally Lipschitzian in X, D H 1 , g X(t), V(t,X, D H 1 , g X(t)) as max{H(X,{0}),H( D H 1 , g X(t),{0})} uniformly for tI. In addition,

lim h 0 + inf 1 h [ V ( t + h , X + h t 0 t F ( s , X , D H 1 , g X ( t ) ) d s , D H 1 , g X ( t ) + h F ( t , X , D H 1 , g X ( t ) ) ) V ( t , X , D H 1 , g X ( t ) ) ] g ( t , V ( t , X ) , V ( t , X ) ) ,
(3.5)

where gC[I× R + × R + ,R];

(C6) the maximal solution r(t, t 0 , u 0 , u 0 ) of problem (3.2) exists on [ t 0 ,) and is positive whenever u 0 , u 0 >0.

Then, for every X 0 , D H 1 , g X( t 0 ) K C (R) such that V( t 0 , X 0 , D H 1 , g X( t 0 ))max{ u 0 , u 0 }, problem (3.1) has a (i-i)-solution X(t) on [ t 0 ,), which satisfies the estimate V(t,X, D H 1 , g X(t))r(t, t 0 , u 0 , u 0 ), t t 0 .

Proof Let S denote the set of all functions X defined on I X =[ t 0 , c X ) with values in K C (R) such that X(t) is a (i-i)-solution of problem (3.1) on I X and V(t,X(t), D H 1 , g X(t))r(t, t 0 , u 0 , u 0 ), t I X . We define a partial order ≤ on S as follows: the relation XY implies that I X I Y and Y(t)X(t) on I X . We shall first show that S is nonempty. Indeed, by assumption (C4), there exists a (i-i)-solution X(t) of problem (3.1) defined on I X =[ t 0 , c X ).

Let X(t)=X(t, t 0 , X 0 , D H 1 , g X( t 0 )) be any (i-i)-solution of (3.1) existing on I X . Define k(t)=V(t,X(t), D H 1 , g X(t)) so that k( t 0 )=V( t 0 , X 0 , D H 1 , g X( t 0 ))max{ u 0 , u 0 }. Now, for small h>0 and using assumption (C5), we consider

k ( t + h ) k ( t ) = V ( t + h , X ( t + h ) , D H 1 , g X ( t + h ) ) V ( t , X ( t ) , D H 1 , g X ( t ) ) V ( t + h , X ( t + h ) , D H 1 , g X ( t + h ) ) + V ( t + h , X + h t 0 t F ( s , X , D H 1 , g X ( t ) ) d s , D H 1 , g X ( t ) + h F ( t , X , D H 1 , g X ( t ) ) ) V ( t + h , X + h t 0 t F ( s , X , D H 1 , g X ( t ) ) d s , D H 1 , g X ( t ) + h F ( t , X , D H 1 , g X ( t ) ) ) V ( t , X ( t ) , D H 1 , g X ( t ) ) L H ( X ( t + h ) , X ( t ) + h t 0 t F ( s , X , D H 1 , g X ( t ) ) d s ) + L H ( D H 1 , g X ( t + h ) , D H 1 , g X ( t ) + h F ( t , X , D H 1 , g X ( t ) ) ) + V ( t + h , X + h t 0 t F ( s , X , D H 1 , g X ( t ) ) d s , D H 1 , g X ( t ) + h F ( t , X , D H 1 , g X ( t ) ) ) V ( t , X ( t ) , D H 1 , g X ( t ) )

using the Lipschitz condition in assumption (C5). Thus

D + k ( t ) lim h 0 + inf 1 h [ k ( t + h ) k ( t ) ] D + V ( t , X ( t ) , D H 1 , g X ( t ) ) + L lim h 0 + inf 1 h H ( X ( t + h ) , X ( t ) + h t 0 t F ( s , X , D H 1 , g X ( t ) ) d s ) + L lim h 0 + inf 1 h H ( D H 1 , g X ( t + h ) , D H 1 , g X ( t ) + h F ( t , X , D H 1 , g X ( t ) ) ) .

Since

lim h 0 + inf 1 h H ( X ( t + h ) , X ( t ) + h t 0 t F ( s , X , D H 1 , g X ( t ) ) d s ) = H ( X ( t ) X ( t + h ) h , t 0 t F ( s , X , D H 1 , g X ( t ) ) d s )

and X(t) is any (i-i)-solution of (3.1), we find that

lim h 0 + inf 1 h H ( X ( t + h ) , X ( t ) + h t 0 t F ( s , X , D H 1 , g X ( t ) ) d s ) = lim h 0 + inf H ( X ( t ) X ( t + h ) h , t 0 t F ( s , X , D H 1 , g X ( t ) ) d s ) = H ( D H g X ( t ) , t 0 t F ( s , X , D H 1 , g X ( t ) ) d s ) = 0 .

On the other hand,

lim h 0 + inf 1 h H ( D H 1 , g X ( t + h ) , D H 1 , g X ( t ) + h F ( t , X , D H 1 , g X ( t ) ) ) = lim h 0 + inf H ( D H 1 , g X ( t ) D H 1 , g X ( t + h ) h , F ( t , X , D H 1 , g X ( t ) ) ) = H ( D H 2 , g X ( t ) , F ( t , X , D H 1 , g X ( t ) ) ) = 0 .

Therefore, we have the scalar differential inequality

D + k(t)g ( t , k ( t ) , k ( t ) ) ,t I X .

We get the estimate

k(t)r ( t , t 0 , u 0 , u 0 ) ,t I X .

It follows that

V ( t , X ( t ) , D H 1 , g X ( t ) ) r ( t , t 0 , u 0 , u 0 ) ,t I X ,
(3.6)

where r(t) is the maximal solution of (3.2). This shows that XS, and so S is nonempty. If ( X β ) β is a chain (S,), then there is a uniquely defined mapping Y on J Y =[ t 0 , sup β c X β ] that coincides with X β on I X β . Clearly, YS and therefore Y is an upper bound of ( X β ) β in (S,). The proof of the theorem is completed if we show that c Z =. Suppose that it is not true, so that c Z <. Since r(t) is assumed to exist on [ t 0 ,), r(t) is bounded on I Z . Since V(t,X(t), D H 1 , g X(t)) as H(X(t),{0}) uniformly in t on [ t 0 , c Z ], the relation V(t,X(t), D H 1 , g X(t))r(t) on I Z implies that H(Z(t),{0}) is bounded on I Z . By assumption (C4), this shows that there is an M>0 such that

H ( F ( t , X ( t ) , D H 1 , g X ( t ) ) , { 0 } ) M,t I Z .

We have, for all t 1 , t 2 I Z with t 1 t 2 ,

H ( Z ( t 2 ) , Z ( t 1 ) ) = H ( I 1 + ( I 2 ( t 2 t 0 ) + t 0 t 2 ( t 0 s F ( τ , Z ( τ ) , D H 1 , g Z ( τ ) ) d τ ) d s ) , I 1 + ( I 2 ( t 1 t 0 ) + t 0 t 1 ( t 0 s F ( τ , Z ( τ ) , D H 1 , g Z ( τ ) ) d τ ) d s ) ) t 1 t 2 t 0 s H ( F ( τ , Z ( τ ) , D H 1 , g Z ( τ ) ) ) d τ M ( t 2 t 1 ) t 1 + t 2 t 0 2 ,

where t 0 t 1 < t 2 . Hence, Z is Lipschitzian on I Z and consequently has a continuous extension Z 0 on [ t 0 , c Z ]. By continuity of Z 0 , we get

Z 0 ( c Z )= I 1 + ( I 2 ( c Z t 0 ) + t 0 c Z ( t 0 s F ( τ , Z ( τ ) , D H 1 , g Z ( τ ) ) d τ ) d s ) .

This implies that Z 0 (t) is a (i-i)-solution of problem (3.1) on [ t 0 , c Z ] and, clearly, V(t, Z 0 (t), D H 1 , g Z 0 (t))<r(t), t[ t 0 , c Z ]. Now, let X 1 = lim t c Z X(t, t 0 , X 0 , D H 1 , g X( t 0 )), D H 1 , g X ( t ) 1 = lim t c Z D H 1 , g X(t, t 0 , X 0 ) and consider the initial problem

D H 2 , g X(t)=F ( t , X ( t ) , D H 1 , g X ( t ) ) ,X( c Z )= X 1 , D H 1 , g X( c Z )= X 1 .

The assumption of local existence implies that there exists a (i-i)-solution X 0 (t) on [ c Z , c Z +δ), δ>0. Define

Z 1 (t)={ Z 0 ( t ) for  t [ t 0 , c Z ] , X 0 ( t ) for  t [ c Z , c Z + δ ) .

Therefore Z 1 (t) is a (i-i)-solution of problem (3.1) on [ t 0 , c Z +δ), and, by repeating the arguments that were used to obtain (3.6), we get V(t, Z 1 (t), D H 1 , g Z 1 (t))r(t), t[ t 0 , c Z +δ). This contradicts the maximality of Z, and hence c Z =+. The proof is complete. □

Remark 3.1 In Theorem 3.3, if (3.5) is replaced by

lim h 0 + inf 1 h [ V ( t + h , X ( 1 ) h t 0 t F ( s , X , D H 1 , g X ( t ) ) d s , D H 1 , g X ( t ) + h F ( t , X , D H 1 , g X ( t ) ) ) V ( t , X , D H 1 , g X ( t ) ) ] g ( t , V ( t , X ) , V ( t , X ) ) ,
(3.7)

then for every X 0 , D H 1 , g X( t 0 ) K C (R) such that V( t 0 , X 0 , D H 1 , g X( t 0 ))max{ u 0 , u 0 }, problem (3.1) has a (ii-i)-solution X(t) on [ t 0 ,), which satisfies the estimate

V ( t , X , D H 1 , g X ( t ) ) r ( t , t 0 , u 0 , u 0 ) ,t t 0 .

Remark 3.2 In Theorem 3.3, if (3.5) is replaced by

lim h 0 + inf 1 h [ V ( t + h , X + h t 0 t F ( s , X , D H 1 , g X ( t ) ) d s , D H 1 , g X ( t ) ( 1 ) h F ( t , X , D H 1 , g X ( t ) ) ) V ( t , X , D H 1 , g X ( t ) ) ] g ( t , V ( t , X ) , V ( t , X ) ) ,
(3.8)

then for every X 0 , D H 1 , g X( t 0 ) K C (R) such that V( t 0 , X 0 , D H 1 , g X( t 0 ))max{ u 0 , u 0 }, problem (3.1) has a (i-ii)-solution X(t) on [ t 0 ,), which satisfies the estimate

V ( t , X , D H 1 , g X ( t ) ) r ( t , t 0 , u 0 , u 0 ) ,t t 0 .

Remark 3.3 In Theorem 3.3, if (3.5) is replaced by

lim h 0 + inf 1 h [ V ( t + h , X ( 1 ) h t 0 t F ( s , X , D H 1 , g X ( t ) ) d s , D H 1 , g X ( t ) ( 1 ) h F ( t , X , D H 1 , g X ( t ) ) ) V ( t , X , D H 1 , g X ( t ) ) ] g ( t , V ( t , X ) , V ( t , X ) ) ,
(3.9)

then for every X 0 , D H 1 , g X( t 0 ) K C (R) such that V( t 0 , X 0 , D H 1 , g X( t 0 ))max{ u 0 , u 0 }, problem (3.1) has a (ii-ii)-solution X(t) on [ t 0 ,), which satisfies the estimate

V ( t , X , D H 1 , g X ( t ) ) r ( t , t 0 , u 0 , u 0 ) ,t t 0 .

Proof One can obtain these results easily by using the same methods as in the proof of Theorem 3.3. □

In next theorem, we present the continuous dependence of the solution on the right-hand side of the equation. First, let us again consider problem (3.1) of the form

D H 2 , g X(t)= F 1 ( t , X ( t ) , D H 1 , g X ( t ) ) ,X( t 0 )= X 0 , D H 1 , g X( t 0 )= X 0 ,
(3.10)

and a problem with another initial value and another right-hand side, i.e.,

D H 2 , g X(t)= F 2 ( t , X ( t ) , D H 1 , g X ( t ) ) ,X( t 0 )= Y 0 , D H 1 , g X( t 0 )= Y 0 .
(3.11)

Theorem 3.4 Assume that X 0 , Y 0 , X 0 , Y 0 K C (R) are nontrivial interval-valued variables and F 1 , F 2 satisfy the conditions of Theorem  2.3. Let X(t, X 0 , X 0 , F 1 ) and X(t, Y 0 , Y 0 , F 2 ) be solutions of (3.10) and (3.11), respectively. Suppose further that there exist constants β, ε such that

H ( F 1 ( t , A , B ) , F 2 ( t , A , B ) ) β

for every (t,A,B)[ t 0 ,T]× K C (R)× K C (R). Then, for every solution X(t, X 0 , X 0 , F 1 ) of (3.10), the following estimation is true:

H ( X ( t , X 0 , X 0 , F 1 ) , X ( t , Y 0 , Y 0 , F 2 ) ) ( α 1 + α 2 T + 3 2 β T 2 ) 1 2 L ( 1 exp ( k ( t 0 T ) ) k ( T t 0 ) exp ( k ( t 0 T ) ) k 2 + 1 exp ( k ( t 0 T ) ) k ) ,

where α 1 =H( X 0 , Y 0 ), α 2 =H( X 0 , Y 0 ).

Proof Setting X F 1 (t)=X(t, t 0 , X 0 , X 0 , F 1 ) and X F 2 (t)=X(t, t 0 , Y 0 , Y 0 , F 2 ), we obtain

H ( X F 1 ( t ) , X F 2 ( t ) ) = H ( X 0 ( 1 ) ( X 0 ( t t 0 ) ( 1 ) t 0 t ( t 0 s F 1 ( τ , X F 1 ( τ ) , D H 1 , g ( X F 1 ) ( τ ) ) d τ ) d s ) , Y 0 ( 1 ) ( Y 0 ( t t 0 ) ( 1 ) t 0 t ( t 0 s F 2 ( τ , X F 2 ( τ ) , D H 1 , g ( X F 2 ) ( τ ) ) d τ ) d s ) ) H ( X 0 , Y 0 ) + ( t t 0 ) H ( X 0 , Y 0 ) + H ( ( 1 ) t 0 t ( t 0 s F 1 ( τ , X F 1 ( τ ) , D H 1 , g ( X F 1 ) ( τ ) ) d τ ) d s , ( 1 ) t 0 t ( t 0 s F 2 ( τ , X F 2 ( τ ) , D H 1 , g ( X F 2 ) ( τ ) ) d τ ) d s ) α 1 + ( t t 0 ) α 2 + t 0 t ( t 0 s H ( F 1 ( τ , X F 1 ( τ ) , D H 1 , g ( X F 1 ) ( τ ) ) , F 2 ( τ , X F 1 ( τ ) , D H 1 , g ( X F 1 ) ( τ ) ) ) d τ ) d s + t 0 t ( t 0 s H ( F 2 ( τ , X F 1 ( τ ) , D H 1 , g ( X F 1 ) ( τ ) ) , F 2 ( τ , X F 2 ( τ ) , D H 1 , g ( X F 2 ) ( τ ) ) ) d τ ) d s α 1 + ( t t 0 ) α 2 + β t ( t t 0 ) 2 + 2 L t 0 t ( t 0 s ( H ( X F 1 ( τ ) , X F 2 ( τ ) ) + H ( D H 1 , g ( X F 1 ) ( τ ) , D H 1 , g ( X F 2 ) ( τ ) ) ) d τ ) d s .
(3.12)

On the other hand, we get

H ( D H 1 , g X F 1 ( t ) , D H 1 , g X F 2 ( t ) ) = H ( X 0 ( 1 ) t 0 t F 1 ( s , X F 1 ( s ) , D H 1 , g X F 1 ( s ) ) d s , Y 0 ( 1 ) t 0 t F 1 ( s , X F 2 ( s ) , D H 1 , g X F 2 ( s ) ) d s ) α 2 + β ( t t 0 ) + 2 L t 0 t ( H ( X F 1 ( s ) , X F 2 ( s ) ) + H ( D H 1 , g X F 1 ( s ) , D H 1 , g X F 2 ( s ) ) ) d s .
(3.13)

Combining (3.12) and (3.13), we have the estimate as follows:

H 0 1 ( X F 1 ( t ) , X F 2 ( t ) ) = H 0 ( X F 1 ( t ) , X F 2 ( t ) ) + H 0 ( D H 1 , g X F 1 ( s ) , D H 1 , g X F 2 ( s ) ) ( α 1 + α 2 T + 3 2 β T 2 ) 1 2 L ( 1 exp ( k ( t 0 T ) ) k ( T t 0 ) exp ( k ( t 0 T ) ) k 2 + 1 exp ( k ( t 0 T ) ) k ) .

 □

It is easily seen that a little change of initial conditions or a little change of the right-hand side of the equation causes a little change of corresponding solutions.

Next, we shall present some examples being simple illustrations of the theory of second-order IDEs. Let us start the illustrations by considering the following second-order IDE:

{ D H 2 , g X ( t ) + a D H 1 , g X ( t ) + b X ( t ) = K ( t ) , X ( t 0 ) = I 1 , D H 1 , g X ( t 0 ) = I 2 ,
(3.14)

where a, b are positive constants, I 1 =[ I ̲ 1 , I ¯ 1 ], I 2 =[ I ̲ 2 , I ¯ 2 ] K C (R), and K(t)=[ K ̲ (t), K ¯ (t)] is a continuous interval-valued function on [ t 0 ,T], and X(t)=[ X ̲ (t), X ¯ (t)]. Our strategy of solving (3.14) is based on the choice of the derivative in the interval-valued differential equation. In order to solve (3.14), we have three steps: first we choose the type of derivative and change problem (3.14) to a system of ODE by using Theorem 2.1 and considering initial values. Second we solve the obtained ODE system. The final step is to find such a domain in which the solution and its derivatives have valid sets, i.e., we ensure that [ X ̲ (t), X ¯ (t)], [ ( X ̲ ) (t), ( X ¯ ) (t)] and [ ( X ̲ ) (t), ( X ¯ ) (t)] are valid sets.

By using Theorem 2.1, we obtain that four ODEs systems are possible for problem (3.14), as follows.

Case 1 X(t) and D H 1 , g X(t) are (i)-differentiable

{ X ̲ ( t ) + a X ̲ ( t ) + b X ̲ ( t ) = K ̲ ( t ) , X ¯ ( t ) + a X ¯ ( t ) + b X ¯ ( t ) = K ¯ ( t ) , X ̲ ( t 0 ) = I ̲ 1 , X ¯ ( t 0 ) = I ¯ 1 , X ̲ ( t 0 ) = I ̲ 2 , X ¯ ( t 0 ) = I ¯ 2 .
(3.15)

Case 2 X(t) is (i)-differentiable and D H 1 , g X(t) is (ii)-differentiable

{ X ¯ ( t ) + a X ̲ ( t ) + b X ̲ ( t ) = K ̲ ( t ) , X ̲ ( t ) + a X ¯ ( t ) + b X ¯ ( t ) = K ¯ ( t ) , X ̲ ( t 0 ) = I ̲ 1 , X ¯ ( t 0 ) = I ¯ 1 , X ̲ ( t 0 ) = I ̲ 2 , X ¯ ( t 0 ) = I ¯ 2 .
(3.16)

Case 3 X(t) is (ii)-differentiable and D H 1 , g X(t) is (i)-differentiable

{ X ¯ ( t ) + a X ¯ ( t ) + b X ̲ ( t ) = K ̲ ( t ) , X ̲ ( t ) + a X ̲ ( t ) + b X ¯ ( t ) = K ¯ ( t ) , X ̲ ( t 0 ) = I ̲ 1 , X ¯ ( t 0 ) = I ¯ 1 , X ̲ ( t 0 ) = I ¯ 2 , X ¯ ( t 0 ) = I ̲ 2 .
(3.17)

Case 4 X(t) and D H 1 , g X(t) are (ii)-differentiable

{ X ̲ ( t ) + a X ¯ ( t ) + b X ̲ ( t ) = K ̲ ( t ) , X ¯ ( t ) + a X ̲ ( t ) + b X ¯ ( t ) = K ¯ ( t ) , X ̲ ( t 0 ) = I ̲ 1 , X ¯ ( t 0 ) = I ¯ 1 , X ̲ ( t 0 ) = I ¯ 2 , X ¯ ( t 0 ) = I ̲ 2 .
(3.18)

Example 3.5 Let us consider the following interval-valued second-order differential equations:

D H 2 , g X(t)=[1,1],X(0)=[1,1], D H 1 , g X(0)=[1,1],t[0,2].
(3.19)

Case 1: From (3.15), we get

{ X ̲ ( t ) = 1 , X ¯ ( t ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 .
(3.20)

By solving (3.20), we obtain X(t)=[( t 2 /2+t+1),( t 2 /2+t+1)] and X (t) are (i)-differentiable. Hence, there is a solution in this case. This solution is shown in Figure 1.

Figure 1
figure 1

Solution of Example 3.5 in Case 1.

Case 2: From (3.16), we have

{ X ¯ ( t ) = 1 , X ̲ ( t ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 .
(3.21)

By solving (3.21), we get X(t)=[( t 2 /2+t+1),( t 2 /2+t+1)] is not (i)-differentiable, there is no solution in this case.

Case 3: From (3.17), we obtain

{ X ̲ ( t ) = 1 , X ¯ ( t ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 .
(3.22)

By solving (3.22), we get X(t)=[( t 2 /2t+1),( t 2 /2t+1)]. Notice that, in this case, since X(t) is (ii)-differentiable and X (t) is (i)-differentiable, such a solution is acceptable. This solution is shown in Figure 2.

Figure 2
figure 2

Solution of Example 3.5 in Case 3.

Case 4: From (3.18), we have

{ X ¯ ( t ) = 1 , X ̲ ( t ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 .
(3.23)

By solving (3.23), we have X(t)=[( t 2 /2t+1),( t 2 /2t+1)] is not (ii)-differentiable on (1,2]. Therefore, there is no solution in this case.

Example 3.6 Let us consider the following interval-valued second-order differential equations:

D H 2 , g X ( t ) + X ( t ) = [ 0 , 2 ] , X ( 0 ) = [ 1 , 1 ] , D H 1 , g X ( 0 ) = [ 1 , 1 ] , t [ 0 , π / 4 ] .
(3.24)

Case 1: From (3.15), we get

{ X ̲ ( t ) + X ̲ ( t ) = 0 , X ¯ ( t ) + X ¯ ( t ) = 2 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 .
(3.25)

By solving (3.25), we obtain X(t)=[(sin(t)+cos(t)),2+sin(t)cos(t)]. Since X (t) is not (i)-differentiable, there is no solution in this case.

Case 2: From (3.16), we have

{ X ¯ ( t ) + X ̲ ( t ) = 0 , X ̲ ( t ) + X ¯ ( t ) = 2 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 .
(3.26)

By solving (3.26), we get X(t)=[(exp(t)exp(t))/2cos(t),2+(exp(t)exp(t))/2cos(t)]. Since, X (t) is not (ii)-differentiable, there is no solution in this case.

Case 3: From (3.17), we obtain

{ X ̲ ( t ) + X ̲ ( t ) = 0 , X ¯ ( t ) + X ¯ ( t ) = 2 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 .
(3.27)

By solving (3.27), we get X(t)=[(exp(t)exp(t))/2cos(t),2(exp(t)exp(t))/2cos(t)]. Notice that, in this case, since X(t) is (ii)-differentiable and X (t) is (i)-differentiable, such a solution is acceptable. This solution is shown in Figure 3.

Figure 3
figure 3

Solution of Example 3.6 in Case 3.

Case 4: From (3.18), we have

{ X ¯ ( t ) + X ̲ ( t ) = 0 , X ̲ ( t ) + X ¯ ( t ) = 2 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 , X ̲ ( 0 ) = 1 , X ¯ ( 0 ) = 1 .
(3.28)

By solving (3.28), we have X(t)=[sin(t)cos(t),2sin(t)cos(t)] and X (t) are (ii)-differentiable. Therefore, the obtained solution is valid. This solution is shown in Figure 4.

Figure 4
figure 4

Solution of Example 3.6 in Case 4.

4 A new method for solving interval-valued second-order differential equations

In [48] the author applied the modification of Laplace decomposition method (LDM) to solve nonlinear interval-valued Volterra integral equations. The modified LDM can be applied to derive the lower and upper solutions. In [46] Salahshour and Allahviranloo solved the second-order fuzzy differential equation under generalized H-differentiability by using fuzzy Laplace transforms. Now, in Section 3 we see that some second-order IDEs are solved under generalized H-differentiability. For the second-order IDEs, there exist at most four solutions, but all the obtained solutions may not be acceptable. It is an important result in the theory of IDEs of higher order. Notice that by applying the above approach (in Section 3), the original second-order IDEs are transformed to four ordinary differential systems. However, by applying Salahshour et al.’s [46] approach, each solution can be obtained directly. In this section, we propose a new algorithm based on the analysis of a crisp solution. We establish a synthesis of a crisp solution of an interval-valued initial value problem and the method proposed in Kaleva [5] and Akin [50].

Let us again consider the interval-valued second-order differential equations of the form

A D H 2 , g X(t)+B D H 1 , g X(t)+CX(t)=F(t),X( t 0 )= I 1 , D H 1 , g X( t 0 )= I 2 ,
(4.1)

where A, B, C are interval-valued constants in K C (R) and X(t), F(t) are interval-valued functions. We define A=[ A ̲ , A ¯ ], B=[ B ̲ , B ¯ ], C=[ C ̲ , C ¯ ] and X(t)=[ X ̲ (t), X ¯ (t)], F(t)=[ F ̲ (t), F ¯ (t)]. Hence we obtain from (4.1)

[ A ̲ , A ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] +[ B ̲ , B ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] +[ C ̲ , C ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] = [ F ̲ ( t ) , F ¯ ( t ) ] .
(4.2)

Then we have

min { [ A ̲ , A ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] + [ B ̲ , B ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] + [ C ̲ , C ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] } = F ̲ (t)

and

max { [ A ̲ , A ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] + [ B ̲ , B ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] + [ C ̲ , C ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] } = F ¯ (t).

From two min and max problems, we notice that it is not an easy task to determine the result of the min and max problems, so we propose the following method.

Step 1: Problem (4.1) is considered as a crisp problem and solved. Here we chose the crisp problem

a x ( t ) + b x ( t ) + c x ( t ) = f ( t ) , x ( t 0 ) = I 1 , x ( t 0 ) = I 2 ,
(4.3)

where x(t) is a real-valued solution of (4.3), aA, bB, cC, I 1 I 1 and I 2 I 2 .

Step 2: Next, we investigate the behavior of the crisp solution x(t) in (4.3) and the following four cases according to domains:

+ Let the domain where x (t)0, x (t)0 be D 1 .

+ Let the domain where x (t)0, x (t)0 be D 2 .

+ Let the domain where x (t)0, x (t)0 be D 3 .

+ Let the domain where x (t)0, x (t)0 be D 4 .

Step 3: After we obtain the four domains above, we set:

+ [ X ̲ (t), X ¯ (t)], [ X ̲ (t), X ¯ (t)] and [ X ̲ (t), X ¯ (t)] in domain D 1 .

+ [ X ̲ (t), X ¯ (t)], [ X ̲ (t), X ¯ (t)] and [ X ¯ (t), X ̲ (t)] in domain D 2 .

+ [ X ̲ (t), X ¯ (t)], [ X ¯ (t), X ̲ (t)] and [ X ¯ (t), X ̲ (t)] in domain D 3 .

+ [ X ̲ (t), X ¯ (t)], [ X ¯ (t), X ̲ (t)] and [ X ̲ (t), X ¯ (t)] in domain D 4 .

Step 4: Substitute the obtained domains in (4.1). Then we obtain that four ODEs systems are possible for problem (4.1), as follows:

Case 1: In domain D 1

{ [ A ̲ , A ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] + [ B ̲ , B ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] + [ C ̲ , C ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] = [ F ̲ ( t ) , F ¯ ( t ) ] , [ X ̲ ( t 0 ) , X ¯ ( t 0 ) ] = [ I ̲ 1 , I ¯ 1 ] , [ X ̲ ( t 0 ) , X ¯ ( t 0 ) ] = [ I ̲ 2 , I ¯ 2 ] .
(4.4)

Case 2: In domain D 2

{ [ A ̲ , A ¯ ] [ X ¯ ( t ) , X ̲ ( t ) ] + [ B ̲ , B ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] + [ C ̲ , C ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] = [ F ̲ ( t ) , F ¯ ( t ) ] , [ X ̲ ( t 0 ) , X ¯ ( t 0 ) ] = [ I ̲ 1 , I ¯ 1 ] , [ X ̲ ( t 0 ) , X ¯ ( t 0 ) ] = [ I ̲ 2 , I ¯ 2 ] .
(4.5)

Case 3: In domain D 3

{ [ A ̲ , A ¯ ] [ X ¯ ( t ) , X ̲ ( t ) ] + [ B ̲ , B ¯ ] [ X ¯ ( t ) , X ̲ ( t ) ] + [ C ̲ , C ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] = [ F ̲ ( t ) , F ¯ ( t ) ] , [ X ̲ ( t 0 ) , X ¯ ( t 0 ) ] = [ I ̲ 1 , I ¯ 1 ] , [ X ¯ ( t 0 ) , X ̲ ( t 0 ) ] = [ I ̲ 2 , I ¯ 2 ] .
(4.6)

Case 4: In domain D 4

{ [ A ̲ , A ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] + [ B ̲ , B ¯ ] [ X ¯ ( t ) , X ̲ ( t ) ] + [ C ̲ , C ¯ ] [ X ̲ ( t ) , X ¯ ( t ) ] = [ F ̲ ( t ) , F ¯ ( t ) ] , [ X ̲ ( t 0 ) , X ¯ ( t 0 ) ] = [ I ̲ 1 , I ¯ 1 ] , [ X ¯ ( t 0 ) , X ̲ ( t 0 ) ] = [ I ̲ 2 , I ¯ 2 ] .
(4.7)

Example 4.1 Consider the following interval-valued second-order differential equation with initial condition:

[2,4] D H 2 , g X(t)=[0,2],X(0)=[1,3], D H 1 , g X(0)=[1,3].
(4.8)

Now, before solving ISDE (4.8), let us solve a crisp problem corresponding to (4.8), to investigate the behavior of a solution. The crisp problem is

3 x (t)=1,x(0)=2, x (0)=2.
(4.9)

A solution for (4.9) is x(t)=(1/6) t 2 +2t+2. The derivatives of a crisp solution are x (t)=(1/3)t+2 and x (t)=1/3. So, for t6, x (t)0 and for any t, x (t)0. Therefore D 1 ={tR|t6}. Similarly, we have D 4 ={tR|t6}. Now, if we substitute the obtained domains in (4.8) for t D 1 , we get the following:

{ [ 2 , 4 ] [ X ̲ ( t ) , X ¯ ( t ) ] = [ 0 , 2 ] , [ X ̲ ( 0 ) , X ¯ ( 0 ) ] = [ 1 , 3 ] , [ X ̲ ( 0 ) , X ¯ ( 0 ) ] = [ 1 , 3 ] .
(4.10)

Then the solution for (4.10) is as follows:

{ X ̲ ( t ) = t + 1 , X ¯ ( t ) = t 2 4 + 3 t + 3 .
(4.11)

Next we must ensure that X ¯ (t) X ̲ (t), X ¯ (t) X ̲ (t) and X ¯ (t) X ̲ (t) for all t6. But X ¯ (t) X ̲ (t) for any t[6,4+2 2 ] and X ¯ (t) X ̲ (t) for any t4. So (4.11) cannot be a solution for (4.8) according to the proposed method. We can see Figure 5. Similarly, we can do the same process for t D 4 . If we substitute the obtained in (4.8) for t D 4 , we get the following:

{ [ 2 , 4 ] [ X ̲ ( t ) , X ¯ ( t ) ] = [ 0 , 2 ] , [ X ̲ ( 0 ) , X ¯ ( 0 ) ] = [ 1 , 3 ] , [ X ¯ ( 0 ) , X ̲ ( 0 ) ] = [ 1 , 3 ] .
(4.12)

Then the solution for (4.12) is as follows:

{ X ̲ ( t ) = 3 t + 1 , X ¯ ( t ) = t 2 4 + t + 3 .
(4.13)

After necessary computations, we see that X ¯ (t) X ̲ (t), X ¯ (t) X ̲ (t) and X ¯ (t) X ̲ (t) for all t6. So, (4.13) is a solution for (4.8) according to the proposed method. In Figure 6, solution curves of (4.8) are given.

Figure 5
figure 5

Solution of Example 4.1.

Figure 6
figure 6

Solution of Example 4.1.

Example 4.2 Consider the following interval-valued second-order differential equation with initial condition:

D H 2 , g X(t)=2 D H 1 , g X(t),X(0)=[2,4], D H 1 , g X(0)=[1,3].
(4.14)

Now, before solving ISDE (4.14), let us solve a crisp problem corresponding to (4.14), to investigate the behavior of a solution. The crisp problem is

x (t)=2 x (t),x(0)=3, x (0)=2.
(4.15)

A solution for (4.15) is x(t)=2+exp(2t). The derivatives of the crisp solution are x (t)=2exp(2t) and x (t)=4exp(2t). So, for any t, x (t)>0 and for any t, x (t)>0. Therefore D 1 =R. Now, if we substitute the obtained domain in (4.14) for t D 1 , we get the following:

{ [ X ̲ ( t ) , X ¯ ( t ) ] = 2 [ X ̲ ( t ) , X ¯ ( t ) ] , [ X ̲ ( 0 ) , X ¯ ( 0 ) ] = [ 2 , 4 ] , [ X ̲ ( 0 ) , X ¯ ( 0 ) ] = [ 1 , 3 ] .
(4.16)

Then the solution for (4.16) is as follows:

{ X ̲ ( t ) = 3 2 + 1 2 exp ( 2 t ) , X ¯ ( t ) = 5 2 + 3 2 exp ( 2 t ) .
(4.17)

Similarly as in Example 4.1, we must ensure that X ¯ (t) X ̲ (t), X ¯ (t) X ̲ (t) and X ¯ (t) X ̲ (t). We obtain X ¯ (t)=3exp(2t), X ̲ (t)=exp(2t) and X ¯ (t)=6exp(2t), X ̲ (t)=2exp(2t). Therefore (4.17) is a solution for (4.14) for any t. We can see Figure 7 ( X ̲ (t) (blue), X ¯ (t) (red) and the crisp solution (black)).

Figure 7
figure 7

Solution of Example 4.2.

5 Conclusions

In this paper, we have obtained a global existence result for a solution to interval-valued second-order differential equations. Also, we have proposed a new algorithm based on the analysis of a crisp solution. The proposed method in this paper may be useful if the coefficients, initial values and forcing terms are interval. If the crisp problem is not solvable explicitly, we cannot determine the mentioned domains precisely.

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Ngo, V.H., Nguyen, D.P. Global existence of solutions for interval-valued second-order differential equations under generalized Hukuhara derivative. Adv Differ Equ 2013, 290 (2013). https://doi.org/10.1186/1687-1847-2013-290

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