In the following, we are ready to provide the main results. First, we investigate the FFDE
via the boundary conditions and , where , , , , and .
Lemma 3.1 Let , , , , and . Then is a solution of the problem
via the boundary conditions
and
if and only if
is a solution of the fractional sum equation
where
whenever or ,
whenever ,
whenever
and
whenever or .
Proof Let be a solution of the problem
via the boundary conditions and . By using Lemma 2.1, we get
Since , we have
Since and
. On the other hand, we have . Thus,
Hence,
and so
(3.1)
(3.2)
To calculate , taking the summation on both sides of the above relation gives us
Hence,
and so by interchanging the order of summations, we have
(3.3)
Since
by replacing (3.3) in (3.1), we get
Now, let be a solution of the fractional sum equation
Then is a solution of the equation
It is easy to check that . Also, we have
Moreover, we have . This completes the proof. □
Some authors tried to find the maximum or exact value of in some papers (see for example [16, 19] and [17]). Now, we show that is bounded, where is the Green function of the last result.
Lemma 3.2 For each and , we have
for some positive number .
Proof Since for all , we have
for all and . Thus, is a (finite) real number, for all , and . Consequently, both sums in the statement are finite, because is finite. □
Theorem 3.3 Let be bounded and continuous in its second and third variables. Then the fractional finite difference equation via the boundary conditions and has a solution with , for all admissible t.
Proof Since g is bounded, there exists a constant C such that for all and . Let be the Banach space of real valued functions defined on via the norm
and . One can check easily that is a compact, convex, and nonempty subset of . Now, define the map T on by
for all . First, we show that . Let and . Then
Since was arbitrary, and so . Now, we show that T is continuous. Let be given. Since g is continuous in its second and third variables, it is uniformly continuous in its second and third variables on and so there exists such that for all and with and . Thus, we get
for all . Hence, and so T is continuous on . By using Theorem 2.2, T has a fixed point and so, by using Lemma 3.1, the fractional finite difference equation
via the boundary conditions and has a solution in . □
Now, we consider the fractional finite difference equation via the boundary conditions , and , where and with .
Lemma 3.4 Let , , , , and with . Then is a solution of the problem via the boundary conditions , , and if and only if is a solution of the fractional sum equation
where
whenever , ,
whenever , ,
whenever , , ,
whenever , and
whenever , .
Proof Let be a solution of the problem via the boundary conditions , , and . By using Lemma 2.1, we get
Similar to the proof of Lemma 3.1, by using the boundary value conditions we obtain ,
and
Thus,
(3.4)
To calculate , by taking the summation on both sides of the above relation gives us
and so
(3.5)
Since and
by replacing (3.5) in (3.4), we get
Now, let be a solution of the fractional sum equation
Similar to proof of the Lemma 3.1, we conclude that is a solution to the problem
via the boundary conditions , , and . This completes the proof. □
By using similar proofs of Lemma 3.2 and Theorem 3.3, we obtain the next results.
Lemma 3.5 For each and , we have
for some positive number .
Theorem 3.6 Assume that is continuous and bounded in its second variable. Then the fractional finite difference equation via the boundary conditions , , and has a solution with , for all admissible t.