In this section, we will state and prove our existence results for BVP (1.1) and (1.2).
Theorem 3.1 Assume the hypotheses (H1)-(H5) hold. Then BVP (1.1) and (1.2) has at least one solution satisfying
(3.1)
and
(3.2)
where C is the constant introduced in Definition 2.1.
To prove Theorem 3.1, firstly, we want to show the following theorems.
Theorem 3.2 There exists at least one solution for BVP (2.18) and (2.19).
Proof By Lemma 2.2, for any , define an operator by
Then we can see that is a solution of BVP (2.18) and (2.19) if and only if is a fixed point of ℋ.
Let with as in E. We want to show that as in E. For f is a Carathéodory function, then it is easy to see . By the Lebesgue dominated convergence theorem, . Let be the unique solution of , where ℒ is given by (2.20). In view of (2.17), there exists such that
(3.3)
From (2.11), (2.14), (2.21) and the continuity of and , we see that is bounded and . Thus, is bounded. If is not convergent, then there exist two convergent subsequences and such that , . Then, by the continuity of and the Lebesgue dominated convergence theorem again, we have
and
which contradicts the fact that . Hence, is convergent, say . Thus, and . As a consequence, we also have
Thus as . This shows that is continuous.
From (3.3) and the fact that is bounded for , this means that ℋ is uniformly bounded on E, and is equicontinuous on J for . Now, we show that is equicontinuous on J. From the definition of ℋ and , we have
Thus, the equicontinuity of follows from the property of absolute of integrals. By the Arzela-Ascoli theorem, we see that is compact. From the Schauder fixed point theorem, ℋ has at least one fixed point , which is a solution of BVP (2.18) and (2.19). We complete the proof. □
Theorem 3.3 If u(t) is a solution of BVP (2.18) and (2.19), then satisfies (3.1).
Proof We first show that on J. To the contrary, suppose that there exists such that . If , then , from (2.19), (H5), (2.12), (2.14), and (2.8), we see that
which is a contradiction. Similarly, if , then , we have
We obtain a contradiction again. Thus, and .
Now, if such that . Then . Without loss of generality, we may assume that . Then and there exists a small right neighborhood Ω of such that and for all . We claim that there exists such that
(3.4)
If this is not true, then is strictly increasing in Ω. Hence, on Ω. This contradicts the assumption that is maximized at . Thus, (3.4) holds.
From (2.7), (2.13), and (2.14), we have , also, by (H4), (2.15), and (2.18), we have
which is a contradiction with (3.4). Thus, on J. By the same method as above, we can show that on J. Hence,
(3.5)
Next, we can see that the following inequality holds:
(3.6)
In fact, assume there exists such that , then, in view of (2.12), . Hence, from (2.19), (H5), (2.8) and (2.12),
This is a contradiction. Thus, for . By a similar argument, we see that for . Then (3.6) holds.
Finally, from (3.5) and integral inequality, we have
and using (3.6), we obtain . Similarly, we can show that satisfies (3.1). The proof is completed. □
Theorem 3.4 If is a solution of BVP (2.18) and (2.19), then satisfies (3.2).
Proof From Theorem 3.3, we know that satisfies (3.1). If (3.2) does not hold, then there exists such that or . By the mean value theorem, there exists such that . Then, from (2.2), (2.3), and (2.17), we see that
If there exist such that , and
(3.7)
where or . In the following, we only consider the case , since the other case can be treated similarly. From (2.14) and (3.7), on I, and in view of (2.11) and (3.1), we have for and . Thus, from (2.15),
Then, by a change of variables and from (2.4) and (2.18), we can obtain
Hence, the Hölder inequality implies
where ζ is defined by (2.6). But this contradicts with (2.5). Therefore, . If , by a similar argument as above, we can show that (3.2) holds. Hence the proof of the theorem is completed. □
Now we are in a position to prove Theorem 3.1.
Proof of Theorem 3.1 Note that any solution of BVP (2.18) and (2.19) satisfying (3.1), (3.2) is a solution of BVP (1.1) and (1.2). The conclusion readily follows from Theorem 3.2-3.4. □